# The Company

At Nike we sell two different types of shoes Nike Lunarglide 6  and Air Jordan 1.  We can sell Lunarglide 6 for \$140 and Air Jordan 1 for \$170.  It costs \$3 to make Lunarglide 6 and uses 6 sq. in. of material.  It costs \$12 to make Air Jordan 1 and uses 6 sq. in. of material. We have 24 sq. in. of material to use.  We have \$10,000 to invest but don't want to spend more than \$150 per day.  We must make at least   How many of each shoe should we make to maximize our profits in one day and how much money would we make.

x= Lunarglide 6

y=Jordan Air 1

Profit= 140 x+170 y

System of Equations: 3x+12y≤150; 6x+6y≤120;

Restrictions: x≥0;y≥0

# Possible Solutions

Lunarglide 6: 0     Air Jordan 1: 20    Profit: \$3,400

Lunarglide 6: 0     Air Jordan 1: 12    Profit: \$2,040

Lunarglide 6: 10     Air Jordan 1: 10   Profit: \$3,100

Lunarglide 6: 20     Air Jordan 1: 0    Profit: \$2,800

Lunarglide 6: 50     Air Jordan 1: 0    Profit: \$7,000

# The Best Combination

The best combination to make the most profit would be to make 5o Lunarglide 6 and it would make you \$7,000.  But if you had to make some of both shoe, you would make 10 Lunarglide 6 and 10 Air Jordan 1 and that would make you only \$3,100.