# AFM NCFE Review Discussion 2

A group of 10 people need to form a line. The line will consist of exactly 9 of the people. Person X and Person Y have to be either fifth or sixth in line.

1. How many different orders are possible?

3. Comment on another post with at least 2 sentences.

5. All posts need to be posted by 9:00pm Sunday, November 23.

### Comment Stream

3 years ago
0

@ahawkins0912 no you will not because there on asking for 2people and that's X and Y. You will multiply them with the other I think.

3 years ago
0

Shaniece Abrams: its still 10 people in the group. Use the formula (n!/n-r!) You will substitute 10 for n

3 years ago
0

8!/7! 40320 * 2!7!

3 years ago
0

phone is messing up when I space it deleats

3 years ago
0

deletes

3 years ago
0

You will have to do permutation which would still be n!/(n!-r!)-r! Not exactly sure about the math for this would be 100 purrcent right but ~ I did 10!/ 3!7 ! Since there are 9 people in the line up you have to take 2 out which gives you 7 so 10-7=3 and for my equation it have me 120 possible outcomes

3 years ago
0

Ronnie I'm not too sure about that but it looks right so good job on that and would love if you could explain it. Thankies btw probably better to type it all together :3

3 years ago
0

Ms.Lynch Im not really sure about the problem but I agree with Tracey that you will have to use the permutation formula to solve it. Sorry I posted late I couldn't get it to come up before tonight.

3 years ago
0

tracey fleming: I agree that the permutation formula will be used for this problem. However I am not quit sure how to solve it

3 years ago
0

Camekia Rawls : That's correct, you will use permutations. But you have to think about how you can make the distinction of c and y being in 5th and 6th place. Read Savoya's post, she has it correct and comment and ask her some questions about her thinking. Thank you for letting me know your technology issue.