My partner and I researched the Slope-Intercept Form...
The line must contain a slope, which is found by rise/run. The line will also express the y-intercept, this is the point where the line crosses the y-axis.
The form of this line can simplify graphing and solving for ordered pairs which are solutions to the equation. It is best known to easily identify the slope and y-intercept.
The equation of the straight line that has slope m = 4
and passes through the point (–1, –6).
Okay, they've given me the value of the slope; in this case, m = 4.
They have also given me an x-value and a y-value for this line: x = –1 and y = –6.
In the slope-intercept form of a straight line, I have y, m, x, and b.
So the only thing I need to figure out is, b (which gives me the y-intercept).
1) Write the formula y = mx + b
2) Plug in (Substitute) the value of the slope .
3) Plug in the given (x,y) point.
4) Solve for b, get b all 5)
5) Re-write the formula with the slope and y-intercept.
y = mx + b
(–6) = (4)(–1) + b
–6 = –4 + b
–2 = b
Then the line equation must be "y = 4x – 2".