Shelby's daycare

Mrs. langford
College Algebra
6th hour

                                                                       Description

I am running a Daycare center and only charging by the week or by the day. X will be the weekly rate and Y will be the daily rate.

                                                                            Costs

It will cost me $20 a day to feed the children two snacks and one lunch. With the $50 a day it will cost me $15 to feed the children two snacks and one lunch.

                                                                         Restrictions

X=50

Y=60

Y_<20

X_<15

                                                                             Profits

60y + 50x = Income

20y + 15x = Cost

40y + 35x = Profit

                                                                      Maximize Profit

*****40(50) + 35(50) = $3750

40(0) + 35(50) = $1750

40(0) + 35(0) = $0

40(50) + 35(0) = $2000

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